2((1)/(2^(x)))(32^(-x))=(1)/(16^(-x))

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Solution for 2((1)/(2^(x)))(32^(-x))=(1)/(16^(-x)) equation: 



2((1)/(2^(x)))(32^(-x))=(1)/(16^(-x))

We move all terms to the left:

2((1)/(2^(x)))(32^(-x))-((1)/(16^(-x)))=0



Domain of the equation: (2^x))(32^(-x))!=0

x∈R





Domain of the equation: (16^(-x)))!=0

x∈R



determiningTheFunctionDomain
2(1/2^x)(32^(-x))-(1/(16^(-x)))=0

We add all the numbers together, and all the variables

2(1/2^x)(32^(-1x))-(1/(16^(-1x)))=0

We calculate fractions


(2(1*(16^(-1x))))/2^x(32^(-1x))*(16^(-1x))))+(-2x)/2^x(32^(-1x))*(16^(-1x))))=0

We can not solve this equation

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